Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Using the z-distribution, as we are working with population data, it is found that:
The 95% confidence interval is -1.38 to 1.38, and 1.74 is outside the interval.
What is the z-distribution confidence interval?
The confidence interval is:
[tex]\overline{x} \pm zs[/tex]
In which:
- [tex]\overline{x}[/tex] is the difference between the population means.
- s is the standard error.
In this problem, we have a 95% confidence level, hence[tex]\alpha = 0.95[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so the critical value is z = 1.96.
The parameters of the interval are given by:
[tex]\overline{x} = 0, s = 0.69[/tex]
Hence, the lower and the upper bound of the interval are given, respectively, as follows:
[tex]\overline{x} - zs = 0 - 1.96(0.69) = -1.38[/tex]
[tex]\overline{x} + zs = 0 + 1.96(0.69) = 1.38[/tex]
The 95% confidence interval is -1.38 to 1.38, and 1.74 is outside the interval.
More can be learned about the z-distribution at https://brainly.com/question/25890103
#SPJ1
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.
