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If 40.0 grams of HCI were dissolved in enough water to make a solution with a total volume of 3.0 liters, what would be the molarity of the solution?

Sagot :

xKelvin

Answer:

About 0.37 M.

Explanation:

Recall that molarity is defined by moles of solute over total liters of solution:
[tex]\displaystyle \text{Molarity} = \frac{\text{ mols solute}}{\text{ L soln.}}[/tex]

Determine the amount of moles of HCl in 40.0 grams. The molecular weight of HCl is 36.46 g/mol:


[tex]\displaystyle 40.0\text{ g HCl} \cdot \frac{1\text{ mol HCl}}{36.46\text{ g HCl}} = 1.10\text{ mol HCl}[/tex]

Therefore, the molarity of the 3.0 L solution is:

[tex]\displaystyle\text{Molarity} = \frac{1.10\text{ mol}}{3.0\text{ L}} =0.37\text{ M}[/tex]

In conclusion, the molarity of the solution is about 0.37 M.

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