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The combustion of propane (C3H8) produces CO₂ and H₂O:
C₂H8 (g) +5O₂ (g) → CO₂ (g) + 4H₂O(g)
The reaction of 5.5 mol of O₂ will produce ____ mol of H2O

Sagot :

Answer:

4.4 moles of water

Explanation:

Propane is C3H8. Is the chemical equation, you wrote C2H8 which is wrong. Type everything properly and give a check before finally posting the question.

The chemical equation that is given, is not properly balanced. The BALANCED equation would be

C3H8 + 5O2 → 3CO2 + 4H2O

From this balanced chemical equation, we see that 5 moles of oxygen produce 4 moles of water.

5 moles of Oxygen → 4 moles of water

1mole of oxygen → [tex]\frac{4}{5}[/tex] moles of water

5.5 moles of oxygen → ([tex]\frac{4}{5}[/tex] × 5.5) moles of water = 4.4 moles of water

∴ The reaction of 5.5 mol of O2 will produce 4.4 mol of H2O. [Answer:]

Answer:

5.5

Explanation:

First, you will need to balance the equation ( the equation in your question is not balanced....typo?)

C2 H8    + 4 O2   ===> 2 CO2   + 4 H2O

Now, from the balanced equation:

O2 : H2O =  4/4 = 1/1

SO   5.5 MOLES  OF  O2  PRODUCES 5.5 MOLES  H20  

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