Answer:
3060 [tex]cm^{2}[/tex]
Step-by-step explanation:
Find the cross-sectional area first of the trapezium
[tex]\frac{1}{2} (a+b)h[/tex]
So, [tex]\frac{1}{2}(6+34)15[/tex]
which is 40 / 2 x 15 = 20 x 15 = 300 [tex]cm^{2}[/tex]
Since there are 2 trapeziums (on the front and back): 300 x 2 = 600[tex]cm^{2}[/tex]
Find the Area of the Rectangles
The first rectangle on the top would be: 6x30 = 180 [tex]cm^{2}[/tex]
The slanted rectangle on the right would be: 25x30 = 750 [tex]cm^{2}[/tex]
The rectangle on the bottom would be: 30x34 = 1020 [tex]cm^{2}[/tex]
The hidden rectangle on the left would be: 17 x 30 = 510 [tex]cm^{2}[/tex]
So by combining all these calculations, you will get the total surface area which is:
600 + 180 + 750 + 1020 + 510 = 780 + 1770 + 510 = 2550 + 510 = 3060 [tex]cm^{2}[/tex]
