Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

there are 13 animals in the barn. some are chickens and some are pigs. there are 40 legs in all. how many of each animal are there?

Sagot :

natcurren17
c=chicken
p=pigs
c+p=13~p=13-c (plug in)
2c+4p=40
2c+4(13-c)=40
2c+52-4c=40
-2c=-12
c=6
6+p=13
p=7
6 chickens
7 pigs
let p = pigs 
and c = chickens 

p + c = 13  ( this is the total number of animals in the barn) 

chicken have 2 legs and pigs have 4 legs 
2c + 4p = 40  ( this is the equation for the total number of legs) 

now lets solve for one variable using the first equation 

p+c = 13
p = 13 -c 

now lets plug that in the 2nd equation
 
2c+4p = 40
2c + 4(13-c) = 40 
2c + 52 - 4c = 40 
now we reduce

-2c = -12

c = 6 
so there are 6 chickens now lets find how many pigs there are by plugging into our first equation

p+6 = 13
p = 7 

so there are 6 chickens and 7 pigs
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.