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Sagot :
The difference between the maximum value of g(x) and the minimum value of f(x) is 5.
Given function is:
[tex]f(x)=x^{2} -2x+8[/tex]......(1)
What is the general form of a quadratic equation?
The general form of a quadratic equation is [tex]ax^{2} +bx+c=0[/tex] with [tex]a\neq 0[/tex].
As we know the minimum value of a quadratic function is [tex]\frac{4ac-b^{2} }{4a}[/tex] when a>0
For f(x) a>0 so minimum value of f(x) = [tex]\frac{4*1*8-(-2)^2}{4*1}[/tex]=7
From the graph, the maximum value of g(x) =12
So, the difference between the maximum value of g(x) and the minimum value of f(x) =12-7 =5
Hence, the difference between the maximum value of g(x) and the minimum value of f(x) is 5.
To get more about quadratic functions visit:
https://brainly.com/question/1214333
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