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A scientist produces zinc iodide (zni2). (a) calculate the minimum mass of zinc that needs to be added to 0.500 g of iodine so that the iodine fully reacts. the equation for the reaction is: zn + i2 ⟶ zni2 relative atomic masses (mr): zn = 65 i = 127

Sagot :

Eduard22sly

The minimum mass of Zinc, Zn that needs to be added to 0.500 g of iodine so that the iodine fully reacts is 0.128 g

Balanced equation

Zn + I₂ —> ZnI₂

Molar mass of Zn = 65 g/mol

Mass of Zn from the balanced equation = 1 × 65 = 65 g

Molar mass of I₂ = 127 × 2 = 254 g/mol

Mass of I₂ from the balanced equation = 1 254 = 254 g

SUMMARY

From the balanced equation above,

254 g of I₂ required 65 g of Zn

How to determine the mass of Zn needed

From the balanced equation above,

254 g of I₂ required 65 g of Zn

Therefore,

0.5 g of I₂ will require = (0.5 × 65) / 254 = 0.128 g of Zn

Thus, the minimum mass of Zn required is 0.128 g

Learn more about stoichiometry:

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