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1. Sound travels through a guitar string at 600 m/s, making a sound wave in the air with a speed of 333 m/s. In 1–2 sentences, explain how the wavelength and frequency of the wave in the string compare to the wavelength and frequency of the wave in the air.

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The wavelength and frequency of the sound in the string is greater than the wavelength and frequency of the sound in the air.

Wavelength and freqeuncy of the sound

The wavelength and frequency of the sound is determined using the following formulas.

v = fλ

f = v/λ

λ = v/f

where;

  • f is the frequency of the sound
  • λ is the wavelength

Wavelength and frequency of the sound in the string

f = 600/λ

λ = 600/f

Wavelength and frequency of the sound in air

f = 333/λ

λ = 333/f

Thus, the wavelength and frequency of the sound in the string is greater than the wavelength and frequency of the sound in the air.

Learn more about wavelength and frequency here: https://brainly.com/question/10728818

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