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solve for x -3(x + 5) = -9

Sagot :

Answer:

[tex]\tt x=-2[/tex]

Step-by-step explanation:

[tex]\tt -3(x + 5) = -9[/tex]

Step (1) :- Distribute

[tex]\tt -3x-15=-9[/tex]

Step (2) :- Add 15 to both sides

[tex]\tt -3x-15+15=-9+15[/tex]

Step (3) :- Simplify

[tex]\tt -3x=6[/tex]

Step (4) :- Divide both sides by -3:-

[tex]\tt \cfrac{-3x}{-3}=\cfrac{6}{-3}[/tex]

[tex]\tt x=-2\;\; \bf Answer[/tex]

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Answer:

[tex] \sf:\implies \quad {\pmb{\sf x = -2}} [/tex]

Solution:

Let's solve the given problem step by step :

[tex]:\implies \quad \sf - 3(x + 5) = - 9[/tex]

First, distribute the given problem :

[tex]:\implies \quad \sf - 3(x + 5) = - 9[/tex]

[tex] \sf:\implies \quad - (3 \times x) - (3 \times 5) = - 9[/tex]

Add 15 to both sides :

[tex] \sf:\implies \quad - 3x - 15 = - 9[/tex]

[tex] \sf:\implies \quad - 3x - 15 + 15 = - 9 + 15[/tex]

On simplifying :

[tex] \sf:\implies \quad -3x-15+15 = -9+15[/tex]

[tex] \sf:\implies \quad - 3x = 6[/tex]

Dividing both sides with same factor :

[tex] \sf:\implies \quad - 3x = 6[/tex]

[tex] \sf:\implies \quad \dfrac{ - 3x}{ - 3} = \dfrac{6}{ - 3} [/tex]

[tex] \sf:\implies \boxed{ \pmb{ \sf\quad x = - 2}}[/tex]

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