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A 12 cm diameter cd has a mass of 21 g. what is the cd's moment of inertia for rotation about a perpendicular axis through the edge of the disk?

Sagot :

nuhulawal20

The moment of inertia for rotation about the perpendicular axis through the edge of the disk is 3.78 × 10⁻⁵ kgm².

Moment of inertia

Moment of inertia is referred to as the product of mass of section and the square of the distance between the reference axis and the centroid of the section.

Moment of inertia of solid cylinder or disk is expressed as;

I = 1/2 × mr²

Given the data in the question;

  • Mass of disk m = 21g = 0.021kg
  • Diameter of disk d = 12cm = 0.12m
  • Radius r = d/2 = 0.12m / 2 = 0.06m
  • Moment of inertia I = ?

We substitute our given value into the expression above.

I = 1/2 × 0.021kg × (0.06m)²

I = 1/2 × 0.021kg × 0.0036m²

I = 3.78 × 10⁻⁵ kgm²

Therefore, the moment of inertia for rotation about the perpendicular axis through the edge of the disk is 3.78 × 10⁻⁵ kgm².

Learn more about Moment of inertia: https://brainly.com/question/19427495

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