Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Calculate the direction cosines of a→+b→, given that a→=4i^+7j^-5k^ and b→=3i^+4j^+k^

Sagot :

batolisis

The direction cosines of a→+b→, are

  • cos ∝ = 0.5232
  • cos β = 0.8065
  • cos γ = 0.2933

Given data:

a = 4i^ + 7j^ - 5k^

b= 3i^ + 4j^ + k^

Calculate the direction cosines of a→+b→

a→+b→ = 7i + 11j - 4k

( a→+b→ ) / | a→+b→ | = ( 7i + 11j - 4k ) / [tex]\sqrt{7^2 + 11^2 + 4^2 }[/tex]

                                = ( 7i + 11j - 4k ) / 13.64

                                = 0.5232 i + 0.8065 j + 0.2933 k

Therefore the direction cosines are

cos ∝ = 0.5232

cos β = 0.8065

cos γ = 0.2933

Hence we can conclude that the direction cosines of a→+b→ are as listed above.

Learn more about direction cosines : https://brainly.com/question/20734777

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.