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Sagot :
The equivalent value of the sum for any value of "x" is 12x - 6
How to find the sum of functions?
Given the sum of the expression as:
3
∑ k(2x-1)
k=0
We need to take the sum of the function at the point where k = 0 to 3
3
∑ k(2x-1) = 0(2x-1) + 1(2x - 1) + 2(2x-1) + 3(2x - 1)
k=0
3
∑ k(2x-1) = 2x-1+4x-2+6x-3
k=0
3
∑ k(2x-1) = 12x - 6
k=0
Hence the equivalent value of the sum for any value of "x" is 12x - 6
Learn more on sum functions here: https://brainly.com/question/24295771
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