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Find the midpoint of BF B(0,-14) F(4,6)

Sagot :

Answer:

Step-by-step explanation:

B(0, -14) ⇒ x₁ = 0 & y₁ = -14

F(4,6) ⇒  x₂ = 4 & y₂ = 6

[tex]Midpoint = \left(\dfrac{x_{1}+x_{2}}{2}, \dfrac{y_{1}+y_{2}}{2} \right)[/tex]

                [tex]=\left(\dfrac{0+4}{2},\dfrac{-14 + 6}{2}\right)\\\\\\= \left(\dfrac{4}{2}, \dfrac{-8}{2} \right)\\\\\\=\left(2, -4 \right)[/tex]

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