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A fighter plane is descending at 30 m/s. The pilot ejects, and the ejector seat accelerates him upwards at 120 m/s2 for 2 seconds. What is his velocity at the end of the 2 seconds?

Sagot :

col7kings

Answer:

210m/s upwards

Explanation:

u= -30m /s

a= 120m/s^2

t=2s

v=u+at

=(-30)+(120x2)

=240-30

=210m/s

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