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Sagot :
Answer:
C = [tex]\frac{963}{92}[/tex]
Step-by-step explanation:
given A varies directly as B and inversely as C then the equation relating them is
A = [tex]\frac{kB}{C}[/tex] ← k is the constant of variation
to find k use the condition A = 6 , B = 10 , C = 15 , then
6 = [tex]\frac{x10k}{15}[/tex] ( multiply both sides by 15 )
90 = 10k ( divide both sides by 10 )
9 = k
A = [tex]\frac{9B}{C}[/tex] ← equation of variation
when A = 92 and B = 107 , then
92 = [tex]\frac{9(107)}{C}[/tex] ( multiply both sides by C )
92C = 963 ( divide both sides by 92 )
C = [tex]\frac{963}{92}[/tex]
Answer:
C = 963/92
Step-by-step explanation:
Given :
- A ∝ B
- A ∝ 1/C
Finding the constant of variation, k
- A = kB/C
- 6 = k(10)/(15) [Given in 1st part of question]
- 6 = 2k/3
- 2k = 18
- k = 9
Finding C
- Using the same equation, and new values of A and B, we can find C
- A = kB/C
- C = kB/A
- C = 9 x 107 / 92
- C = 963/92
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