summerh36
Answered

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How many solutions are there?

How Many Solutions Are There class=

Sagot :

semsee45

Answer:

no solution

Step-by-step explanation:

Solve:

6(2k + 1) = 12k + 1

Expand brackets:

⇒  12k + 6 = 12k + 1

Subtract 12k from both sides:

⇒  6 = 1

As 6 ≠ 1 there is no solution

Answer:

No solution

Step-by-step explanation:

Simplify the L.H.S and the R.H.S

⇒ [tex]6(2k + 1) = 12k + 1[/tex]

⇒ [tex]12k + 6 = 12k + 1[/tex]

Cancel out the "12k"

⇒ [tex]12k + 6 = 12k + 1[/tex]

⇒ [tex]6 = 1 (\text{False})[/tex]

Henceforth, this equation has no solution.

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