Answered

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Find the values of x for which the denominator is equal to zero for 2x^2+5/x^2-2x .

x = 0, x = 2

x = 1, x = 2

none

x = 2

Sagot :

Let's see

[tex]\\ \rm\rightarrowtail x^2-2x=0[/tex]

[tex]\\ \rm\rightarrowtail x(x-2)=0[/tex]

[tex]\\ \rm\rightarrowtail x=0\:or\:x-2=0[/tex]

[tex]\\ \rm\rightarrowtail x=0\:or\:x=2[/tex]

AllanBrecken

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[tex] \green{••••••••••••••••••••••} \blue{••••••••••••••••••••••••••}[/tex]

[tex] \sf {x^2 - 2x = 0} [/tex]

[tex] \sf {x ( x - 2) = 0} [/tex]

[tex] \sf {x = 0 \: or \: x-2 = 0} [/tex]

[tex] \sf \green{ {x = 0 \: or \: x = 2}} [/tex]

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