Answered

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Find an equation for the plane that contains the line and is perpendicular to the plane

Sagot :

MrRoyal

For the line and the plane to be perpendicular, they have to meet at right angles

The equation for the plane is x + 2y + 3z= 26

How to determine the equation?

From the complete question, we have:

Point = (5,0,7)

Plane perpendicular to ⟨1,2,3⟩

The general equation is:

a * x+b * y+c * z = d

So, we have:

d = 5 * 1 + 2 * 0 + 7 * 3

Evaluate

d = 26

Recall that:

d = 5 * 1 + 2 * 0 + 7 * 3

Replace the points with x, y and z.

So, we have:

d = x * 1 + 2 * y + 3 * z

Evaluate

d = x + 2y + 3z

So, we have:

d = x + 2y + 3z and d = 26

Equate both equations

x + 2y + 3z= 26

Hence the equation for the plane is x + 2y + 3z= 26

Read more about perpendicular planes at:

https://brainly.com/question/4954460

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