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Sagot :
The voltage as a function of time for the power source oscillating at the given frequency is determined as V = 169.7sin(120πt).
Peak voltage
The peak voltage of the source is calculated as follows;
Vrms = 0.7071V₀
120 = 0.7071V₀
V₀ = 120/0.7071
V₀ = 169.7 V
Angular frequency of the wave
ω = 2πf
where;
f is frequency = 60 Hz
ω = 2π x 60
ω = 120π rad/s
Voltage equation as function of time
V = V₀sin(ωt)
V = 169.7sin(120πt)
Learn more about peak voltage here: https://brainly.com/question/6249123
The voltage equation is a function of a time is V = 169.7sin(120πt) if the 1. 5-kω resistor and 27. 7-mh inductors are connected in series to a vrms = 120 v ac power source oscillating at a frequency of f = 60 Hz.
What is induced voltage?
Electromagnetic induction causes the induced voltage. Electromagnetic induction is the process of creating emf (induced voltage) by exposing a conductor to a magnetic field.
We have:
[tex]\rm V{rms} = 120[/tex]
We know:
[tex]\rm V_{rms} = 0.7071V_o[/tex]
[tex]\rm 120 = 0.7071V_o[/tex]
[tex]\rm V_o = 169.70[/tex] Volts
Expression for the angular frequency is given by:
ω = 2πf
Where f is frequency
ω = 2π x 60
ω = 120π rad/s
Voltage equation as a function of time is given by:
V = V₀sin(ωt)
V = 169.7sin(120πt)
Thus, the voltage equation is a function of a time is V = 169.7sin(120πt) if the 1. 5-kω resistor and 27. 7-mh inductors are connected in series to a vrms = 120 v ac power source oscillating at a frequency of f = 60 Hz.
Learn more about the induced voltage here:
brainly.com/question/19482771
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