Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

10 A fixed quantity of gas is placed inside a container of fixed volume at a temperature of
27°C. The gas has a pressure, P.
Which expression shows the pressure of the gas at 57°C?
A P2=(27/57) P
B
P2=(57/27) P
P2=(300/330) P
с
D
P2=(330/300) P

Sagot :

dsdrajlin

A gas has a pressure P at 27 °C. To calculate its pressure at 57°C we use an expression derived from Gay-Lussac's law:

C) P2 = (300/330) P

What does Gay-Lussac's law state?

Gay-Lussac's law states that the pressure of a given mass of gas varies directly with the absolute temperature of the gas when the volume is kept constant.

Mathematically, it can be written as:

P/T = k

A gas has a pressure P at 27 °C and we want to find the expression to calculate its pressure at 57°C.

  • Step 1: Convert the temperatures to the Kelvin scale.

We do so by summing 273.15.

K = 27 + 273.15 = 300 K

K = 57 + 273.15 = 330 K

  • Step 2: Apply Gay-Lussac's law.

P2/330 = P/300

P2 = (300/330) P

A gas has a pressure P at 27 °C. To calculate its pressure at 57°C we use an expression derived from Gay-Lussac's law:

C) P2 = (300/330) P

Learn more about Gay-Lussac's law here: https://brainly.com/question/24691513

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.