Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A globe has a diameter of 12 inches. It fits inside a cube-shaped box that has a side length of 12 inches.

​What is the volume, rounded to the nearest hundredth of a cubic inch, of the space inside the box that is not taken up by the globe?


Sagot :

The volume, rounded to the nearest hundredth of a cubic inch, of the space inside the box that is not taken up by the globe is 823.68 inches³

Volume of a sphere

The globe is a sphere. Therefore, the volume is as follows:

volume = 4 / 3 πr³

where

r = 12  /2 = 6 inches

volume = 4 / 3 × π × 6³

volume = 864 / 3 π

volume = 288 × 3.14  = 904.32inches³

Volume of a cube

The box is a cube. Therefore,

volume = L³

where

  • L = length

Therefore,

volume = 12³

volume = 1728 inches³

Therefore, the volume of the space inside the box that is not taken up by the globe is as follows:

volume not taken up = 1728 - 904.32 = 823.68 inches³

learn more on volume here: https://brainly.com/question/15385003