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if 146.5 g of chromium(lll) chlorate decomposes, what mass of oxygen can be produced?

Sagot :

Answer:

The Equation for this reaction is as follow,

                               2 Cr(ClO₃)₃    →    2 CrCl₃  +  9 O₂

According to eq,

      604.68 g (2mole) of Cr(ClO₃)₃ produces  =  288 g (9 moles) of O₂

So,

                 146.5 g of Cr(ClO₃)₃ will produce  =  X g of O₂

Solving for X,

                             X  = (146.5 g × 288 g) ÷ 604.68 g

                    X  =  69.77 g of O₂

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