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how many grams of kclo3 are needed to make 30.0 grams of kcl

Sagot :

Eduard22sly

The mass of  potassium chlorate, KClO₃ needed to produce 30 grams of potassium chloride, KCl is 49.33 grams

Balanced equation

2KClO₃ —> 2KCl + 3O₂

Molar mass of KClO₃ = 39 + 35.5 + (16×3) = 122.5 g/mol

Mass of KClO₃ from the balanced equation = 2 × 122.5 = 245 g

Molar mass of Kcl= 39 + 35.5 = 74.5 g/mol

Mass of KCl from the balanced equation = 2 × 74.5 = 149 g

SUMMARY

From the balanced equation above,

149 g of KCl were obtained from 245 g of KClO₃

How to determine the mass of KClO₃ needed

From the balanced equation above,

149 g of KCl were obtained from 245 g of KClO₃

Therefore,

30 g of KCl will be obtained from = (30 × 245) / 149 = 49.33 g of KClO₃

Thus, 49.33 g of KClO₃ are needed for the reaction

Learn more about stoichiometry:

https://brainly.com/question/14735801

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