rowie15
Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

One number is 4 less than 3 times a second number. If 3 more than two times the first number is decreased by two times the second, the result is 11. What are both numbers?

Sagot :

thisisbenmanley
The 1st number is x and the 2nd number is y:

x = 3y-4
3 + 2x - 2y = 11

The first equation says that x is equal to "3y - 4", so you can plug in "3y - 4" for x in the second equation:

3 + 2(3y - 4) - 2y = 11
3 + 6y - 8 - 2y = 11
-5 + 4y = 11
4y = 16
y = 4

Now that you have y, you can plug it into the 1st equation to get x:

x = 3y - 4
x = 3(4) - 4
x = 12 - 4
x = 8

So, the 1st number is 8 and the 2nd number is 4.
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.