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When aluminum oxidizes in air, it forms aluminum oxide (Al2O3):

4Al(s)+3O2(g)→2Al2O3(s)

A 102 g sheet of aluminum oxide formed completely in excess oxygen.

How many grams of aluminum were oxidized?


27 g


51 g


54 g


102 g


Sagot :

Answer:

54g

Explanation:

al= 27gmol-1

al 2mol=54g

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