Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

100 points! please help me will mark brainliest

100 Points Please Help Me Will Mark Brainliest class=

Sagot :

S + O2 → SO2

Moles of S:

11/32.06 = 0.3431 mol

Moles of O2:

44/15.999 = 2.75 mol

Sulfur will be the limiting reagent.

Oxygen will be the excess reagent

2.75 - 0.3431 = 2.4071 mols of oxygen leftover

2.4071 * 15.999 = 38.511

38.511 grams of oxygen will be leftover

indrawboy

Reaction

S + O₂ ⇒ SO₂

mole S = 11 : 32 g/mol = 0.34375

mole O₂ = 44 : 32 g/mol = 1.375

S as a limiting reactant (smaller) and converted all to sulfur dioxide

mole O₂ (unreacted) = 1.375 - 0.34375 = 1.03125

mass O₂ (unreacted) = 1.03125 x 32 = 33 g

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.