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How many moles of H2O can be produced when 2.75 moles of O2 react with an excess of NH3?

Sagot :

The number of moles of H₂O that could be produced is 3.3 moles

Stoichiometry

From the question, we are to determine the number of moles of H₂O that could be produced

First, we will write the balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

4NH₃ + 5O₂ → 4NO + 6H₂O

This means,

4 moles of NH₃ reacts with 5 moles of O₂ to produce 4 moles of NO and 6 moles of H₂O

Now,

If 4 moles of NH₃ reacts with 5 moles of O₂ to produce 6 moles of H₂O

Then,

Excess NH₃ will react with 2.75 moles of O₂ to produce x moles of H₂O

x = [tex]\frac{2.75 \times 6}{5}[/tex]

x = 3.3 moles

Hence, the number of moles of H₂O that could be produced is 3.3 moles

Learn more on Stoichiometry here: https://brainly.com/question/14271082

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