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An experimenter adds 336 J of heat to a 56.2 g sample of Hg. What is its change in temperature? The heat capacity of Hg is .139 J/g·°C.

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samueladesida43

The change in temperature if an experimenter adds 336 J of heat to a 56.2 g sample of Hg is 43.01°C.

HOW TO CALCULATE SPECIFIC HEAT CAPACITY?

The change in temperature of a substance can be calculated using the following expression;

Q = mc∆T

where;

  • Q = quantity of heat absorbed or released (J)
  • m = mass of substance (g)
  • ∆T = change in temperature (°C)

According to this question, an experimenter adds 336 J of heat to a 56.2 g sample of Hg. The change in temperature is calculated as follows:

∆T = 336J ÷ (56.2 × 0.139)

∆T = 43.01°C

Therefore, the change in temperature if an experimenter adds 336 J of heat to a 56.2 g sample of Hg is 43.01°C.

Learn more about change in temperature at: https://brainly.com/question/2530523

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