t8cneyqgrt
Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

50 POINTS PLUS BRAINLY

50 POINTS PLUS BRAINLY class=

Sagot :

fieryanswererft

Answer:

[tex]\sf x= 55.7^\circ \:[/tex]

using tan rule:

[tex]\hookrightarrow \sf tan(x) = \dfrac{opposite}{adjacent}[/tex]

[tex]\hookrightarrow \sf tan(x) = \dfrac{22}{15}[/tex]

[tex]\hookrightarrow \sf x= tan^{-1}(\dfrac{22}{15} )[/tex]

[tex]\hookrightarrow \sf x = 55.7^\circ \:[/tex]

semsee45

Answer:

55.7° (nearest tenth)

Step-by-step explanation:

Use tan trig ratio:

[tex]\tan(\theta)=\dfrac{O}{A}[/tex]

where [tex]\theta[/tex] is the angle, O is the side opposite the angle and A is the side adjacent the angle.

Given:

  • [tex]\theta[/tex] = [tex]x[/tex]
  • O = 22
  • A = 15

[tex]\implies \tan(x)=\dfrac{22}{15}[/tex]

[tex]\implies x=\arctan\left(\dfrac{22}{15}\right)[/tex]

[tex]\implies x=55.7 \textdegree[/tex]

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.