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Please help fast! AB=?

Please Help Fast AB class=

Sagot :

indrawboy

∠A = 180° - (63°+101°)=16°

sine's rule

[tex]\tt \dfrac{AB}{sin~C}=\dfrac{BC}{sin~A}\\\\\dfrac{AB}{sin~63}=\dfrac{9}{sin~16}\\\\AB=29.09[/tex]

clarch19

Answer:

AB = 29

Step-by-step explanation:

Law of Sines:

[tex]\frac{9}{sin 16}[/tex] = [tex]\frac{x}{sin 63}[/tex]

cross-multiply:

x·sin(16°) = 9·sin(63°)

x = [tex]\frac{9sin63}{sin16}[/tex]

x = 29

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