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N2 + 3H2 - 2NH3
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If 150.0 grams of ammonia were produced how many moles of N2 would be needed?

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Sagot :

The number of mole of nitrogen gas, N₂, needed to produce 150 g of ammonia, NH₃ is 4.41 moles

How to determine the mole of NH₃ produced

  • Mass of NH₃ = 150 g
  • Molar mass of NH₃ = 14 + (3×1) = 17 g/mol
  • Mole of NH₃ =?

Mole = mass /molar mass

Mole of NH₃ = 150 / 17

Mole of NH₃ = 8.82 moles

How to determine the mole of N₂ needed

Balanced equation

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

2 moles of NH₃ were produced by 1 mole of N₂.

Therefore,

8.82 moles of NH₃ will be produced by = 8.82 / 2 = 4.41 moles of N₂.

Thus, 4.41 moles of N₂ is  needed for the reaction.

Learn more about stoichiometry:

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