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If C=r+7 and D=-2r+3, find an expression that equals 2C−D in standard form.

Sagot :

ᴜᴋɪʏᴏ

Answer:

[tex]\huge\boxed{\boxed{\bf\:4r + 11}}[/tex]

Step-by-step explanation:

Given,

  • C = r + 7
  • D = - 2r + 3

We need to find the value of 2C - D. To solve this, we need to substitute the values of C & D in the expression.  So,

[tex]\tt\:2\:C - D\\\\\sf\:{Substitute \: the \: given \: values}\\\\\tt\:= 2(r + 7) - (-2r + 3)\\\\\sf\:Now, \: follow \: the \: distributive \:property\\\\\tt\:= 2r + 14 + 2r - 3\\\\\sf\:Rearrange\:the\:terms\\\\\tt\:= 2r + 2r + 14 - 3\\\\\sf\:Do \: the \: required \:arithmetic \: operations\\\\=\boxed{ \bf\:4r + 11}[/tex]

[tex]\rule{200}{2}[/tex]

  • The answer will be 4r + 11 in the standard form.

[tex]\rule{200}{2}[/tex]

Hope this helps!

MrRoyal

The expression that equals 2C - D is 4r+ 11

How to determine the expression

The expressions are given as:

C=r+7 and D=-2r+3

The expression 2C - D is calculated as follows:

2C - D = 2 * (r + 7)  - (-2r + 3)

Expand

2C - D = 2r + 14  +2r - 3

Collect like terms

2C - D = 2r +2r+ 14   - 3

Evaluate the like terms

2C - D = 4r+ 11

Hence, the expression that equals 2C - D is 4r+ 11

Read more about expressions at:

https://brainly.com/question/4344214

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