Answered

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During a lie detector test, a voltage of 6V is impressed across two fingers. When a certain question is asked, the resistance between the fingers drops, from 400,000 ohms, to 200,000 ohms. What is the current (a) initially through the fingers, and (b) when the resistance between them drops?
a) .000015 amps
b) .00003 amps

Sagot :

batolisis

The current initially through the fingers is : 1.5 * 10⁻⁵ amp

The current when the resistance between them drops is : 3 * 10⁻⁵ amp

Given data :

Voltage ( V ) = 6 V

Initial resistance ( r ) = 400,000 ohms

Final resistance ( R ) = 200,000 ohms

Determine The Current

A) initially through fingers

I = V / r

 = 6 V / 400,000

 = 1.5 * 10⁻⁵ amp

B) when the resistance between them drops

I = V / R

 = 6 V / 200000

 = 3 * 10⁻⁵ amp

Hence we can conclude that The current initially through the fingers is : 1.5 * 10⁻⁵ amp and The current when the resistance between them drops is : 3 * 10⁻⁵ amp

Learn more about current calculation : https://brainly.com/question/25922783

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