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a blackbody is radiating with a characteristic wavelength of 9 microns what is the blackbody temperature answer in kelvin

Sagot :

This question involves the concepts of Wein's displacement law and characteristic wavelength.

The blackbody temperature will be "3.22 x 10⁵ k".

WEIN'S DISPLACEMENT LAW

According to Wein's displacement law,

[tex]\lambda_{max} T = c\\\\T=\frac{c}{\lambda_{max}}[/tex]

where,

  • [tex]\lambda_{max}[/tex] = characteristic wavelength = 9 μm = 9 x 10⁻⁹ m
  • T = temperature = ?
  • c = Wein's displacment constant = 2.897 x 10⁻³ m.k

Therefore,

[tex]T=\frac{2.897\ x\ 10^{-3}\ m.k}{9\ x\ 10^{-9}\ m}[/tex]

T = 3.22 x 10⁵ k

Learn more about characteristic wavelength here:

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