Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

In going from a texas summer room temperature (35. 0°c) to 10°c above room temperature, the rate of a reaction quadruples (increases by a factor of 4). Calculate the activation energy for the reaction.

Sagot :

Based on the information given, it has been computed that the activation energy will be 105.8Kj.

How to calculate activition energy

From the information given,

T1 = 25 + 273 = 298K

T2 = 35 + 273 = 308J

R = 8.314J/mol

K2/K1 = 4

Therefore,

log(4) = E/(2.303 × 8.314) × [10/(298 × 308)]

= (0.602 × 2.303 × 8.314 × 298 × 308) / 10

= 105.8KJ

Therefore, the activation energy is 105.8KJ.

Learn more about activation energy on:

https://brainly.com/question/1380484

We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.