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The strength of the electric field 0. 5 m from a 6 µC charge is _______ N/C. (Use k = 8. 99 × 109 N•meters squared per Coulomb squared and round answer to the nearest whole number. ) 215760 539400 697976 512356.

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hamzaahmeds

This question involves the concepts of electric field strength and distance.

The strength of the electric field is "215760 N/C".

STRENGTH OF ELECTRIC FIELD

The electric field strength due to a charge is given by the following formula:

[tex]E = \frac{kq}{r^2}[/tex]

where,

  • E = Electric Field Strength = ?
  • k = Colomb's constant = 8.99 x 10⁹ N.m²/C²
  • q = magnitude of charge = 6 μC = 6 x 10⁻⁶ C
  • r = distance = 0.5 m

Therefore,

[tex]E=\frac{(8.99\ x\ 10^9\ N.m^2/C^2)(6\ x\ 10^{-6}\ C)}{(0.5\ m)^2}[/tex]

E = 215760 N/C

Learn more about electric field strength here:

https://brainly.com/question/4264413

shubhamchouhanvrVT

This question involves the concepts of electric field strength and distance.The strength of the electric field is "215760 N/C".

What is the Strength of Electric Field?

The electric field strength due to a charge is given by the following formula:

[tex]E=\dfrac{kq}{r^2}[/tex]

where,

E = Electric Field Strength = ?

k = Colomb's constant = 8.99 x 10⁹ N.m²/C²

q = magnitude of charge = 6 μC = 6 x 10⁻⁶ C

r = distance = 0.5 m

Therefore, putting the values in the formula;

[tex]E=\dfrac{(8.99\times 10^9)(6\times 10^{-6})}{0.5}[/tex]

E = 215760 N/C

Thus the strength of the electric field is "215760 N/C".

Learn more about electric field strength here:

brainly.com/question/4264413

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