Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

How fast was a driver going if the car left skid marks that were 48 feet long on dry concrete? (The coefficient of friction is 1.02)?
A) 31 mph
B) 38 mph
C) 49 mph
D) 73 mph

Sagot :

semsee45

Answer:

B) 38 mph

Step-by-step explanation:

s = √(30df)

s is the speed the car was traveling (in mph)

d is the distance the car skidded (in feet)

f is the coefficient of friction

s = √(30 x 48 x 1.02)

s = 38.32492661... = 38

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.