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Charlie the Chemist heats a 62.51 g piece of copper from 22.9°C to 345.0°C. Calculate the amount
of heat absorbed by the piece of metal (with correct significant figures and sign). Show your work,
Note: The specific heat of copper is 0.0920 cal(g°C), and cal is the abbreviation for calorie.

Sagot :

  • Mass=m=62.51g
  • Initial temperature=T_i=22.9°C
  • Final temperature=T_f=345.0°C
  • Specific heat of copper=0.0920cal/g°C
  • ∆T=T_f-T_i=345-22.9=322.1°C

[tex]\\ \tt\hookrightarrow Q=mc\Delta T[/tex]

[tex]\\ \tt\hookrightarrow Q=62.1(0.0920)(322.1)[/tex]

[tex]\\ \tt\hookrightarrow Q=1840.22172cal[/tex]

[tex]\\ \tt\hookrightarrow Q=1840.222cal[/tex]

[tex]\\ \tt\hookrightarrow Q=1840.2cal[/tex]

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