Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Need question 14 I'm confused on what the teacher wants.

Need Question 14 Im Confused On What The Teacher Wants class=

Sagot :

In part A, we simply replace the variable A with 326

This is because A represents the number of vehicles in thousands.

So we go from this [tex]A = 2x^2+22x+326[/tex] to this [tex]326 = 2x^2+22x+326[/tex]

Answer: [tex]326 = 2x^2+22x+326[/tex]

==========================================

For part B, we'll subtract 326 from both sides

[tex]326 = 2x^2+22x+326\\\\326-326 = 2x^2+22x+326-326\\\\0 = 2x^2+22x\\\\2x^2+22x = 0[/tex]

Then we can factor out the GCF 2x and solve for x.

[tex]2x^2+22x = 0\\\\2x(x+11) = 0\\\\2x = 0 \text{ or } x+11 = 0\\\\x = 0 \text{ or } x = -11[/tex]

What does this tell us? It says that for years x = 0 and x = -11, the amount of vehicles purchased was A = 326 thousand.

We ignore x = -11 because that would mean we rewind 11 years into the past, but the instructions say "x years after 1980". In other words, 1980 is the farthest in time we can go back. That corresponds to the year x = 0.

In short, the only practical solution here is x = 0. It says 326 thousand cars were purchased in 1980.

Answer:  1980