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The Problem Is In The Picture class=

Sagot :

Answer:

x = 3 or 7

Step-by-step explanation:

Solve by completing the square:

[tex]x^2 - 10x + 1 = -20[/tex]

First, move the constants to one side:

[tex]x^2 - 10x = -21[/tex]

Then, add [tex](\frac{-10}{2})^2[/tex] to both sides to make the right a perfect square trinomial, which is easy to factor:

[tex]x^2 - 10x + (\frac{-10}{2})^2 = -21 + (\frac{-10}{2})^2[/tex]

Simplify and Factor:

[tex]x^2 - 10x + 25 = -21 + 25[/tex]

[tex](x - 5)^2 = 4[/tex]

Finally, square root both sides using the even roots property:

[tex]\sqrt{(x - 5)^2} = \sqrt{4}[/tex]

x - 5 = ± 2

x = 5 ± 2

x = 3   or   x = 7

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