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Sagot :
So, the work done by her is 631.12 J.
Introduction
Hello ! I will help you regarding energy and its transformation. In this case, it's the use of energy from the lifter to be equivalent to potential energy, because the box undergoes a change in height and the potential energy specializes at a certain height. Work (W) due to change in potential energy ([tex] \sf{\Delta PE} [/tex]) can be realized in the equation :
[tex] \sf{W = \Delta PE} [/tex]
[tex] \sf{W = m \cdot g \cdot h_2 - m \cdot g \cdot h_2} [/tex]
[tex] \boxed{\sf{\bold{W = m \cdot g \cdot (h_2 - h_1)}}} [/tex]
With the following condition :
- W = work (J)
- m = mass of the objects (kg)
- [tex] \sf{h_2} [/tex] = final height of object (m)
- [tex] \sf{h_1} [/tex] = initial height of object (m)
- g = acceleration of the gravity (m/s²)
Problem Solving
We know that :
- m = mass of the objects = 23 kg
- [tex] \sf{h_2} [/tex] = final height of object = 2.8 m
- [tex] \sf{h_1} [/tex] = initial height of object = 0 m
- g = acceleration of the gravity = 10 m/s²
What was asked :
- W = work = ... J
Step by Step :
[tex] \sf{W = m \cdot g \cdot (h_2 - h_1)} [/tex]
[tex] \sf{W = 23 \cdot 9.8 \cdot (2.8 - 0)} [/tex]
[tex] \sf{W = 23 \cdot 9.8 \cdot 2.8} [/tex]
[tex] \boxed{\sf{W = 631.12 \: J}} [/tex]
So, the work done by her is 631.12 J.
See More :
- Another example of calculating the energy required to lift an object https://brainly.com/question/26487284
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