Step-by-step explanation:
[tex]\large \sf\color{pink}{Given \: Question:-}\\ \\ \large \sf \color{pink}{ 1)To \: find \: perimeter \: of \: given \: figure} \\ \\
\large \sf\color{pink}{2)To \: find \: area \: of \: given \: figure} \\ \\ \large \sf\color{grey}{lets \: solve \: ↠} \\ \\ \large \color{pink}\boxed{\sf{Perimeter↠}} \\ \\ \sf\underline{⇒ We \: know \: that \: perimeter \: of \: a \: shape \: is \: equal \: to \: the \: sum \: of \: all \: sides} \\ \\ \large \sf{⇒10 + 12 + 7 + 6} \\ \\ \large \sf{⇒22 + 13} \\ \\ \large \boxed{\sf{⇒35}} \\ \\ \\ \large \color{pink} \boxed {\sf{Area↠}} \\ \\ \large \sf\underline{⇒\: to \: find \: area \: divide \: the \: shape \: into \: two \: rectangles \: nd \: then \: add} \\ \\ \large \sf\underline{⇒\:soo \: we \: know \: that \: area \: of \: rectangle \: = length \times breadth} \\ \\ \large \sf{⇒10 \times 12} \\ \\ \large \sf{⇒120sq.cm} \\ \\ \large \sf{nd} \\ \\ \large \sf{⇒7 \times 6} \\ \\ \large \sf{⇒42sq.cm} \\ \\ \large \sf{⇒120 + 42(now \: added)} \\ \\ \large \boxed{\sf{⇒162sq.cm}} \\ \\ \\ \large \color{lightgreen} \boxed { \sf{Perimeter \: of \: given \: shape =35cm }} \\ \\ \large \color{lightgreen} \boxed { \sf{ Area\: of \: given \: shape = 162sq.cm }} \\ \\ [/tex]
[tex]\large\color{red}{\boxed{❥\:gℓσssүρεαяℓ...}}[/tex]
