At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Taking into account the reaction stoichiometry, 1.729 grams of NaCl is formed.
Reaction stoichiometry
In first place, the balanced reaction is:
CuCl₂ + 2 NaNO₃ → Cu(NO₃)₂ + 2 NaCl
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- CuCl₂: 1 mole
- NaNO₃: 2 moles
- Cu(NO₃)₂ : 1 mole
- NaCl: 2 moles
The molar mass of the compounds is:
- CuCl₂: 134.44 g/mole
- NaNO₃: 85 g/mole
- Cu(NO₃)₂ : 187.54 g/mole
- NaCl: 58.45 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- CuCl₂: 1 mole ×134.44 g/mole= 134.44 grams
- NaNO₃: 2 moles ×85 g/mole= 170 grams
- Cu(NO₃)₂ : 1 mole ×187.54 g/mole= 187.54 grams
- NaCl: 2 moles ×58.45 g/mole= 116.9 grams
Mass of NaCl formed
The following rule of three can be applied: If by stoichiometry of the reaction 134.44 grams of CuCl₂ form 116.9 grams of NaCl, 2 grams of CuCl₂ form how much mass of NaCl?
[tex]mass of NaCl=\frac{2 grams of CuCl_{2}x116.9 grams of NaCl }{134.44grams of CuCl_{2}}[/tex]
mass of NaCl= 1.739 grams
Finally, 1.729 grams of NaCl is formed.
Learn more about the reaction stoichiometry:
brainly.com/question/24741074
brainly.com/question/24653699
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.