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Sagot :
Answer:
[tex] {3x}^{2} + 5x + 2 \\ = {3x}^{2} + 3x + 2x + 2 \\ = 3x(x + 1) + 2(x + 1) \\ = (3x +2)(x + 1)[/tex]
Answer:
x=-2/3 and x=-1
factored form
(3x+2)(x+1)
[Let me know if there is another method your instructor wanted you to use]
Step-by-step explanation:
Given:
[tex]3x^2+5x+2=0[/tex]
Factor using the quadratic formula:
[tex]x=\frac{-b+-\sqrt{b^2-4(a)(c)} }{2a}[/tex]
[tex]x=\frac{-5+-\sqrt{(5)^2-4(3)(2)} }{2(3)}[/tex]
[tex]x=\frac{-5+-\sqrt{25-24} }{6}[/tex]
[tex]x=\frac{-5+-\sqrt{1} }{6}[/tex]
[tex]x=\frac{-5+1}{6}[/tex] and [tex]x=\frac{-5-1}{6}[/tex]
Finally:
[tex]x=-2/3[/tex] and [tex]x=-1[/tex]
Written in factored form would be:
[tex](3x+2)(x+1)[/tex]
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