Answered

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Consider the following method:

public static void mystery(int[] data) {
for (int i = 1; i < data.length - 1; i++) {
if (data[i] == data[i - 1] + data[i + 1]) {
data[i] = data[i] / 2;
}
}
}

For each array below, indicate what the array's contents would be after the method mystery were called and passed that array as its parameter.


{3, 7, 4}
{0, 3, 7, 4, 1}
{4, 3, 8, 5, 1, 2}
{2, 1, 5, 4, 10, 6, 2}
{1, 2, 1, 2, 1, 2, 1}

Sagot :

MrRoyal

The array contents after the method mystery were called are:

  • {3,3,4}
  • {0,3,3,2,1}
  • {4,3,4,2,1,2}
  • {2, 1, 2, 4, 5, 6, 2}
  • {1, 1, 1, 1, 1, 1, 1}

How to determine the array contents

The flow of the mystery method is as follows:

  • The method takes an array as its argument
  • It iterates from the elements at index 1 through index n - 1 (n represents the array length)
  • If the current element in the iteration adds up to the adjacent elements, the current element is halved.

Using the above flow, the array contents after the method mystery were called are: {3,3,4}, {0,3,3,2,1}, {4,3,4,2,1,2}, {2, 1, 2, 4, 5, 6, 2} and {1, 1, 1, 1, 1, 1, 1}

Read more about arrays at:

https://brainly.com/question/15683939

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