Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
The given sequence the recursive function will be [tex]a_n = 4a_{n-1}[/tex]
The iterative rule for the sequence is [tex]T_n = 8(4)^{n-1[/tex]
Sequence and series
Given the sequence of numbers 8, 32, 128, 512, …
- a1 = 8
- a2 = 32 = 4(8)
- a3 = 128 = 4(32)
From the given sequence the recursive function will be [tex]a_n = 4a_{n-1}[/tex]
For the iterative sequence, we will use the common ratio and the first term as shown;
[tex]T_n=ar^{n-1}\\T_n=8(4)^{n-1}[/tex]
Hence the iterative rule for the sequence is [tex]T_n = 8(4)^{n-1[/tex]
Learn more on sequence here: https://brainly.com/question/7882626
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.