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what is 8x + 10 ≤ 51 please show work

Sagot :

[tex]\huge\fbox{Hi~there!~:)}[/tex]

Let's solve this inequality! :)

Let's start by subtracting 10 from both sides:

[tex]\rm{8x\leq 51-10}[/tex]

[tex]\rm{8x\leq 41[/tex]

Now, divide both sides by 8:

[tex]x\leq \displaystyle\frac{41}{8}[/tex] (Answer)

Decimal form:

[tex]\rm{5.125}[/tex]

I hope you find it helpful.

Feel free to ask if you have any doubts.

[tex]\bf{-MistySparkles^**^*[/tex] here to help

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