Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

What are the solutions to the quadratic equation below?
X^2 +13x + 40 =0
A. X = -10 and x = 4
B. X= 10 and X = 4
C. X = 8 and x = -5
o
D. X = -8 and x = -5

Sagot :

tajudeenoseni

Using factorization method;

x²+13x+40=0

x²+13+40

Find two numbers that you can add together to give the co-efficient of variable x. (I.e 13 for this question). Also, you'll find two numbers that you can multiply with each other to give you the whole number as an answer. (I.e 40 in this question). The two numbers must be the same (i.e the two numbers that will be added to give the co-efficient of x and the two numbers that will be multiplied to give the whole number must be the same two).

The two numbers are +5 and +8

The equation will therefore be = x²+5x+8x+40

You'll then factorize (I.e use a common factor of both values to bracket them)

x(x+5)+8(x+5)

(x+8)(x+5)

x is therefore (x+8=0) or (x+5=0)

x=(x=0-8) or (x=0-5)

x= -8 or x= -5

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.