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Sagot :
The distance from point C to point D is -0.25.
Given
Point C is located at (1, 2) and point D is located at (−4, −2).
Let Coordinates of A= (x, y)
A point is located 1/4 the distance from C to D.
So the remaining distance from point A to D is 3/4
Thus the ratio of CA : AD = m :n = 1: 3
What is the section formula?
When point C divides a segment AB in the ratio m:n, we use the section formula to find the coordinates of that point.
[tex]\rm Distance \ from \ point \ C\ to \ D = \dfrac{mx_1+nx_2}{m+n}\\\\ Distance \ from \ point \ C\ to \ D = \dfrac{1(-4)+3(1)}{1+3}\\\\ Distance \ from \ point \ C\ to \ D = \dfrac{-4+3}{5}\\\\ Distance \ from \ point \ C\ to \ D = \dfrac{-1}{5}\\\\ Distance \ from \ point \ C\ to \ D = -0.25[/tex]
Hence, the distance from point C to point D is -0.25.
To know more about the Section formula click the link given below.
https://brainly.com/question/26239726
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