malhefeiti696
Answered

Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

can anyone help me to solve the question

Can Anyone Help Me To Solve The Question class=

Sagot :

Answer:

x = 2[tex]\sqrt{10}[/tex]

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is

x² + 9² = 11²

x² + 81 = 121 ( subtract 81 from both sides )

x² = 40 ( take square root of both sides )

x = [tex]\sqrt{40}[/tex] = [tex]\sqrt{4(10)}[/tex] = [tex]\sqrt{4}[/tex] × [tex]\sqrt{10}[/tex] = 2[tex]\sqrt{10}[/tex] ≈ 6.32 ( to 2 dec. places )

Binay5524

Answer:

I think the image above will help you.

View image Binay5524
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.